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ErikH63
Resolver I
Resolver I

Displaying an Integer as a Hexadecimal?

Hello, 

 

I though this was a no-brainer, maybe it is and I am missing the obvious, but I have integers in my powerapp canvas form that I need to display as a hexadecimal, but I am not finding anything just the Excel dec2hex.  I am not working with the hex number just displaying. Any ideas?

 

For example 30 =  0x1E

 

Thanks for any help.  -Erik

1 ACCEPTED SOLUTION

Accepted Solutions

@ErikH63 

There is no decimal to hex function in PowerApps unfortunately.  You will have to perform the math in your app to do the conversion.  There are several direct and indirect methods to conversion, so it really depends on what you are up for.  If your numbers will be 2 digit hex (less than 256) then it is pretty straight forward.  If not, then it gets a little challenging.

 

With({_value: 255,
      _digits:["0","1","2","3","4","5","6","7","8","9","A","B","C","D","E","F"]},

   Last(FirstN(_digits, RoundDown(_value / 16 , 0)+1)).Value &
   Last(FirstN(_digits, Mod(_value, 16)+1)).Value

)

Would provide FF as the result based on the _value of 255.

 

You can use this and replace the _value with whatever your number is coming from.  Also, this can be used in a component as a function for your app.  Again though, this is all simple hex with decimals less than 256.

 

I hope this is helpful for you.

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View solution in original post

6 REPLIES 6

@ErikH63 

There is no decimal to hex function in PowerApps unfortunately.  You will have to perform the math in your app to do the conversion.  There are several direct and indirect methods to conversion, so it really depends on what you are up for.  If your numbers will be 2 digit hex (less than 256) then it is pretty straight forward.  If not, then it gets a little challenging.

 

With({_value: 255,
      _digits:["0","1","2","3","4","5","6","7","8","9","A","B","C","D","E","F"]},

   Last(FirstN(_digits, RoundDown(_value / 16 , 0)+1)).Value &
   Last(FirstN(_digits, Mod(_value, 16)+1)).Value

)

Would provide FF as the result based on the _value of 255.

 

You can use this and replace the _value with whatever your number is coming from.  Also, this can be used in a component as a function for your app.  Again though, this is all simple hex with decimals less than 256.

 

I hope this is helpful for you.

_____________________________________________________________________________________
Digging it? - Click on the Thumbs Up below. Solved your problem? - Click on Accept as Solution below. Others seeking the same answers will be happy you did.
NOTE: My normal response times will be Mon to Fri from 1 PM to 10 PM UTC (and lots of other times too!)
Check out my PowerApps Videos too! And, follow me on Twitter @RandyHayes

Really want to show your appreciation? Buy Me A Cup Of Coffee!
ErikH63
Resolver I
Resolver I

Thank you for confirming that @RandyHayes .   I did seem to find an option in Power Automate flow with "format number".  It is amazing that this function is not in powerapps.  

RexMidas
Regular Visitor

It might be a bit to late, but I'll post my answer here for future reference.
If you want to convert any decimal to hex:
Concat(
ForAll(
Sequence(RoundUp(Log(Value(<yourvalue>)+1,16),0),RoundUp(Log(Value(<yourvalue>)+1,16),0),-1),
{result:Last(FirstN(["0","1","2","3","4","5","6","7","8","9","A","B","C","D","E","F"],(Mod(RoundDown(Value(<yourvalue>)/Power(16,ThisRecord.Value-1),0),16)+1))).Value}),
result&"")

I'm also late, but here's another solution for folks who are dealing with colors stored as integers that you need converted to hex for HTML elements. The two suggestions given work already, but face problems if you're working with values that don't take up all 6 spaces. The With statement on the outside is just for demo purposes, and you can remove it if you don't need it.

 

 

With(
    {color:16777215}, // white
    Concat(
        ForAll(
            [RoundDown(color/65536,0),RoundDown(Mod(color,65536)/256,0),RoundDown(Mod(Mod(color,65536),256),0)] As ColorPart,
            Concat(
                ForAll(
                    [RoundDown(ColorPart.Value/16,0),RoundDown(Mod(ColorPart.Value,16),0)],
                    With({a: Mod(ThisRecord.Value,16)},
                        {hex:If(a<10,Text(a),Switch(a,10,"A",11,"B",12,"C",13,"D",14,"E","F"))}
                    )
                ),
                hex&""
            )
        ),
        Value
    )
)

 

If your data source has a different configuration, like Delphi (which uses BBGGRR instead of RRGGBB), you can just change the order of the elements in the OrderPart array (and if you want RGBA instead, just use the array parts as your RGB portion and set A to whatever you want).

 

[RoundDown(Mod(Mod(color,65536),256),0),RoundDown(Mod(color,65536)/256,0),RoundDown(color/65536,0)] As ColorPart // BBGGRR version

 

HankanmanTM
Regular Visitor

//

Hankanman212
Regular Visitor

Old post but I just came up with a super simple way using the JSON() (wasn't available at the time of the original post):

 

Right(Substitute(JSON(RGBA(0,0,0,0.23)),"""",""),2)

 

Replace "0.23" with the number you want to convert as a percentage of 255 so 0 returns "00", 1 returns "ff", 0.23 returns "3a"

For extra style points, you can make it a User-Defined Function:

 

DecToHex(Decimal:Number):Text = Right(Substitute(JSON(RGBA(0,0,0,Decimal)),"""",""),2);

 

You can then use this anywhere in the app to get a hex value:

 

DecToHex(0.23)

 

This then returns the string "3a" and if you need it in upper case you can simply do:

 

Upper(DecToHex(0.23))

 

Which returns "3A"

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