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MAnil850071
Frequent Visitor

Save collection to SharePoint list as a single row

Hi All,

 

Would there be an option to patch a collection column values to a SharePoint list as a single row, instead of individual rows per collection row. Let's say I have collection with 3 records  they are addtasks and my SharePoint list contain task  columns. like task1 , task2,task3, these 3 are lookup columns in sharepoint list. i need to map those  addtasks collection into these list how to implement it please guide me.

 

11 REPLIES 11
cha_cha
Super User
Super User

Hello    @MAnil850071 

 

The function you will need for this is Concat. For Example, if you have a collection named colSP and it has 3 records, as you said Task1, Task2, Task3, and these values are stored in a column named TaskName

  

You can use Concat like this to store the values above as "Task1,Task2,Task3"Concat(colSP, TaskName,",") 

However, if you have multiple columns, it might be best that you learn JSON.

 

JSON allows you to store data structure as a string in SharePoint:

An Intro by Reza Dorrani here: https://www.youtube.com/watch?v=FqfLiJDdC3Q


 
Just in case my answer helped you solve your problem, please mark/accept this as a SOLUTION This helps community members if they experience a similar issue in the future.

 
bistek.space   @charv3n    @BisTekSpace 
developerAJ
Resident Rockstar
Resident Rockstar

@MAnil850071 

 

 

You need to store json data of collection in Text Format and store in multilinetext column.

when you get the data you need to parse it using ParseJson(experimental Feature) or use Split function to Split.

 

Example :

developerAJ_1-1685457196434.png

 

As shown in pic i took a collection with Title and currency column converted into format similar to Json.

 

 

Set(varJson,Concat(collection,"{"&Char(34)&"Title"&Char(34)&":"&Char(34)&""&ThisRecord.Title&""&Char(34)&","&Char(34)&"Currency"&Char(34)&":"&Char(34)&""&ThisRecord.Currency&""&Char(34)&"}",","));
Set(varJson,"[
    "&varJson&"
]");
Patch(Test,First(Test),{Json:varJson})

 

 

When retrieving data:

 

ForAll( Table(ParseJSON(First(Test).Json)), { Title: Text(ThisRecord.Value.Title), Currency: Text(ThisRecord.Value.Currency) } )

 

 

instead of parse json if you want to use concat seperator as any other symbol like ; it will help you to split rows

 

Please click Accept as solution and Thumbs Up. if my post helped you solve your issue. This will help others find it more readily. It also closes the item. If the content was useful in other ways, please consider giving it Thumbs Up.

Please click Accept as solution and give it Thumbs Up if my post helped you solve your issue. This will help others find it more readily. It also closes the item. If the content was useful in other ways, please consider giving it Thumbs Up.
Connect with me on Linkedin : DeveloperAJ

Hi thanks for your response i implemented 

ForAll(colselectedRows,Patch('Start/Ending',Defaults('Start/Ending'),{Task1:{'Id':colselectedRows[@ID],
'Value':colselectedRows[@Name]},Task2:{'Id':colselectedRows[@ID],
'Value':colselectedRows[@Name]},Task3:{'Id':colselectedRows[@ID],
'Value':colselectedRows[@Name]}}));
 

In this code I can getting records but it's creating multiple records in SharePoint list  tell me if anything I need to change here

 

developerAJ
Resident Rockstar
Resident Rockstar

@MAnil850071 

 

above code creates a record for each item in colselectedRows:

if colselectedRows has 4 items it will create 4 items in SharePoint

Please click Accept as solution and give it Thumbs Up if my post helped you solve your issue. This will help others find it more readily. It also closes the item. If the content was useful in other ways, please consider giving it Thumbs Up.
Connect with me on Linkedin : DeveloperAJ

Yes exactly but here I need share single record in SharePoint how do I achieve it please tell me 

developerAJ
Resident Rockstar
Resident Rockstar

@MAnil850071 

 

One solution is above Json solution i expained.

 

if its 3 task only.

add another column to collection lets say iteration: 1, 2 , 3

use that for look up formula ex: Task1: lookup(collection,iteration:1)

 

Please click Accept as solution and Thumbs Up. if my post helped you solve your issue. This will help others find it more readily. It also closes the item. If the content was useful in other ways, please consider giving it Thumbs Up.

Please click Accept as solution and give it Thumbs Up if my post helped you solve your issue. This will help others find it more readily. It also closes the item. If the content was useful in other ways, please consider giving it Thumbs Up.
Connect with me on Linkedin : DeveloperAJ

Above code I'm getting 3 records only sorry to say I'm not much aware about json function can you please explain more detailed.

developerAJ
Resident Rockstar
Resident Rockstar

you can use the below suggestion
You need to store json data of collection in Text Format and store in multilinetext column.

when you get the data you need to parse it using ParseJson(experimental Feature) or use Split function to Split.

 

Example :

developerAJ_0-1685464456948.png

 

 

As shown in pic i took a collection with Title and currency column converted into format similar to Json.

 

 

Set(varJson,Concat(collection,"{"&Char(34)&"Title"&Char(34)&":"&Char(34)&""&ThisRecord.Title&""&Char(34)&","&Char(34)&"Currency"&Char(34)&":"&Char(34)&""&ThisRecord.Currency&""&Char(34)&"}",","));
Set(varJson,"[
    "&varJson&"
]");
Patch(Test,First(Test),{Json:varJson})

 

 

When retrieving data:

 

ForAll( Table(ParseJSON(First(Test).Json)), { Title: Text(ThisRecord.Value.Title), Currency: Text(ThisRecord.Value.Currency) } )

 

 

instead of parse json if you want to use concat seperator as any other symbol like ; it will help you to split rows

Please click Accept as solution and give it Thumbs Up if my post helped you solve your issue. This will help others find it more readily. It also closes the item. If the content was useful in other ways, please consider giving it Thumbs Up.
Connect with me on Linkedin : DeveloperAJ

im getting error  while trying to save data

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