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zulfa_r
Advocate I
Advocate I

Random Password

How to create random password in PAD

3 ACCEPTED SOLUTIONS

Accepted Solutions

Hi @zulfa_r ,

 

There is an action called Create Random Text action this you can use to create random password.

You just need to set the length of password required.

Please find the below solution.

VishnuReddy1997_0-1717206047897.png

 

(Note:- if you got your solution you can mark as solution and gives kudos)


Thanks & Regards

Vishnu Reddy

View solution in original post

Hi,

 

Refer this solution.

Solved: Re: How to generate random password in power autom... - Power Platform Community (microsoft....

 

If I have answered your question, please mark it as the preferred solution. If you like my response, please give it a Thumbs Up.

Regards,
Riyaz

View solution in original post

AK88
Responsive Resident
Responsive Resident

Hi @zulfa_r ,

 

Also, try with PAD action 'Create Random Text' to generate random string in a variable. Sharing the screenshot below. Hope both methods will suitable for your query. 

 

AK88_2-1717308887430.png

 

 

thanks,

if it resolved your query, kindly mark it as solution and give thumps Up!

View solution in original post

7 REPLIES 7
eetuRobo
Memorable Member
Memorable Member

There is no actions to do that since creating passwords/user credentials are not really tasks you would normally want automate.


You could do it via script. For example I just asked ChatGPT to create such a VBScript and seemed to work:

eetuRobo_0-1717159185195.png

 


VBScript code:

 

 

Function GenerateRandomPassword(length)
    Dim chars, password, i, rndIndex
    chars = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789!@#$%%^&*()_+-=[]{}|;':,./<>?" 'characters to be used in the randomized password

    Randomize
    password = ""
    For i = 1 To length
        rndIndex = Int((Len(chars) - 1) * Rnd + 1)
        password = password & Mid(chars, rndIndex, 1)
    Next
    GenerateRandomPassword = password
End Function

Dim length, password
length = 12 ' Set your desired password length here
password = GenerateRandomPassword(length)

' return password to VBScriptOutput
WScript.Echo password

 

 

 
That creates random 12 character password with special characters and letters(capitalized and not) and numbers

eetuRobo_1-1717158944568.png

 

Hi @zulfa_r ,

 

There is an action called Create Random Text action this you can use to create random password.

You just need to set the length of password required.

Please find the below solution.

VishnuReddy1997_0-1717206047897.png

 

(Note:- if you got your solution you can mark as solution and gives kudos)


Thanks & Regards

Vishnu Reddy

Hi,

 

Refer this solution.

Solved: Re: How to generate random password in power autom... - Power Platform Community (microsoft....

 

If I have answered your question, please mark it as the preferred solution. If you like my response, please give it a Thumbs Up.

Regards,
Riyaz

AK88
Responsive Resident
Responsive Resident

Hi @zulfa_r,

kindly check the below snippet of code , this will create a random password with shuffling with different character types including special symbols. Hope it works.

 

 

 

 

Function GenerateRandomPassword(length)
    Dim upperChars, lowerChars, numberChars, specialChars
    Dim password, i, rndIndex
    Dim requiredChars, tempArray(), shuffled
    Dim strLen

    ' Characters to be used in the randomized password
    upperChars = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
    lowerChars = "abcdefghijklmnopqrstuvwxyz"
    numberChars = "0123456789"
    specialChars = "!@#$%^&*()_+-=[]{}|;':,./<>?"

    Randomize
    password = ""

    ' Ensure at least one character from each category
    password = Mid(upperChars, Int(Len(upperChars) * Rnd + 1), 1)
    password = password & Mid(lowerChars, Int(Len(lowerChars) * Rnd + 1), 1)
    password = password & Mid(numberChars, Int(Len(numberChars) * Rnd + 1), 1)
    password = password & Mid(specialChars, Int(Len(specialChars) * Rnd + 1), 1)

    ' Remaining characters to fulfill the desired length
    requiredChars = upperChars & lowerChars & numberChars & specialChars

    For i = 5 To length ' Start from 5 since we already added 4 characters
        rndIndex = Int(Len(requiredChars) * Rnd + 1)
        password = password & Mid(requiredChars, rndIndex, 1)
    Next

    ' Shuffle the password to avoid predictable order
    shuffled = ShuffleString(password)

    GenerateRandomPassword = shuffled
End Function

Function ShuffleString(str)
    Dim i, pos, temp, strLen
    Dim tempArray()
    strLen = Len(str)
    ReDim tempArray(strLen - 1)

    For i = 1 To strLen
        tempArray(i - 1) = Mid(str, i, 1)
    Next

    For i = 0 To UBound(tempArray)
        pos = Int((UBound(tempArray) + 1) * Rnd)
        temp = tempArray(i)
        tempArray(i) = tempArray(pos)
        tempArray(pos) = temp
    Next

    ShuffleString = JoinArray(tempArray)
End Function

Function JoinArray(arr)
    Dim result, i
    result = ""
    For i = LBound(arr) To UBound(arr)
        result = result & arr(i)
    Next
    JoinArray = result
End Function

Dim length, password
length = 12
password = GenerateRandomPassword(length)


WScript.Echo password

 

 

Also check with PAD on this action 'Create Random Text', this will also give a designated result, Kindly check.

AK88_0-1717307410872.png

 

thanks,

If my solution resolved your query, kindly mark it as solution and give thumps up!

AK88
Responsive Resident
Responsive Resident

Hi @zulfa_r ,

 

Kindly check the below snippet of code using Vb script to generate the random string as Password, which includes all character types as required.

 

 

 

Function GenerateRandomPassword(length)
    Dim upperChars, lowerChars, numberChars, specialChars
    Dim password, i, rndIndex
    Dim requiredChars, tempArray(), shuffled
    Dim strLen

    ' Characters to be used in the randomized password
    upperChars = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
    lowerChars = "abcdefghijklmnopqrstuvwxyz"
    numberChars = "0123456789"
    specialChars = "!@#$%^&*()_+-=[]{}|;':,./<>?"

    Randomize
    password = ""

    ' Ensure at least one character from each category
    password = Mid(upperChars, Int(Len(upperChars) * Rnd + 1), 1)
    password = password & Mid(lowerChars, Int(Len(lowerChars) * Rnd + 1), 1)
    password = password & Mid(numberChars, Int(Len(numberChars) * Rnd + 1), 1)
    password = password & Mid(specialChars, Int(Len(specialChars) * Rnd + 1), 1)

    ' Remaining characters to fulfill the desired length
    requiredChars = upperChars & lowerChars & numberChars & specialChars

    For i = 5 To length ' Start from 5 since we already added 4 characters
        rndIndex = Int(Len(requiredChars) * Rnd + 1)
        password = password & Mid(requiredChars, rndIndex, 1)
    Next

    ' Shuffle the password to avoid predictable order
    shuffled = ShuffleString(password)

    GenerateRandomPassword = shuffled
End Function

Function ShuffleString(str)
    Dim i, pos, temp, strLen
    Dim tempArray()
    strLen = Len(str)
    ReDim tempArray(strLen - 1)

    For i = 1 To strLen
        tempArray(i - 1) = Mid(str, i, 1)
    Next

    For i = 0 To UBound(tempArray)
        pos = Int((UBound(tempArray) + 1) * Rnd)
        temp = tempArray(i)
        tempArray(i) = tempArray(pos)
        tempArray(pos) = temp
    Next

    ShuffleString = JoinArray(tempArray)
End Function

Function JoinArray(arr)
    Dim result, i
    result = ""
    For i = LBound(arr) To UBound(arr)
        result = result & arr(i)
    Next
    JoinArray = result
End Function

Dim length, password
length = 12 ' Set your desired password length here
password = GenerateRandomPassword(length)

' Return password to VBScriptOutput
WScript.Echo password

 

 

 

Also, try with PAD action 'Create Random Text' to generate random string in a variable. Sharing the screenshot below. Hope both methods will suitable for your query. 

 

AK88_0-1717307866651.png

thanks,

if it resolved your query, kindly mark it as solution and give thumps Up!

AK88
Responsive Resident
Responsive Resident

Hi @zulfa_r ,

 

Kindly check the below snippet of code using Vb script to generate the random string as Password, which includes all character types as required.

 

@@copilotGeneratedAction: 'False'
DISABLE Scripting.RunVBScript.RunVBScript VBScriptCode: `Function GenerateRandomPassword(length)
    Dim upperChars, lowerChars, numberChars, specialChars
    Dim password, i, rndIndex
    Dim requiredChars, tempArray(), shuffled
    Dim strLen

    ' Characters to be used in the randomized password
    upperChars = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
    lowerChars = "abcdefghijklmnopqrstuvwxyz"
    numberChars = "0123456789"
    specialChars = "!@#$%^&*()_+-=[]{}|;':,./<>?"

    Randomize
    password = ""

    ' Ensure at least one character from each category
    password = Mid(upperChars, Int(Len(upperChars) * Rnd + 1), 1)
    password = password & Mid(lowerChars, Int(Len(lowerChars) * Rnd + 1), 1)
    password = password & Mid(numberChars, Int(Len(numberChars) * Rnd + 1), 1)
    password = password & Mid(specialChars, Int(Len(specialChars) * Rnd + 1), 1)

    ' Remaining characters to fulfill the desired length
    requiredChars = upperChars & lowerChars & numberChars & specialChars

    For i = 5 To length ' Start from 5 since we already added 4 characters
        rndIndex = Int(Len(requiredChars) * Rnd + 1)
        password = password & Mid(requiredChars, rndIndex, 1)
    Next

    ' Shuffle the password to avoid predictable order
    shuffled = ShuffleString(password)

    GenerateRandomPassword = shuffled
End Function

Function ShuffleString(str)
    Dim i, pos, temp, strLen
    Dim tempArray()
    strLen = Len(str)
    ReDim tempArray(strLen - 1)

    For i = 1 To strLen
        tempArray(i - 1) = Mid(str, i, 1)
    Next

    For i = 0 To UBound(tempArray)
        pos = Int((UBound(tempArray) + 1) * Rnd)
        temp = tempArray(i)
        tempArray(i) = tempArray(pos)
        tempArray(pos) = temp
    Next

    ShuffleString = JoinArray(tempArray)
End Function

Function JoinArray(arr)
    Dim result, i
    result = ""
    For i = LBound(arr) To UBound(arr)
        result = result & arr(i)
    Next
    JoinArray = result
End Function

Dim length, password
length = 12 ' Set your desired password length here
password = GenerateRandomPassword(length)

' Return password to VBScriptOutput
WScript.Echo password` ScriptOutput=> VBScriptOutput

 

 

 

 

Also, try with PAD action 'Create Random Text' to generate random string in a variable. Sharing the screenshot below. Hope both methods will suitable for your query. 

 

AK88_1-1717308733593.png

 

thanks,

if it resolved your query, kindly mark it as solution and give thumps Up!

AK88
Responsive Resident
Responsive Resident

Hi @zulfa_r ,

 

Also, try with PAD action 'Create Random Text' to generate random string in a variable. Sharing the screenshot below. Hope both methods will suitable for your query. 

 

AK88_2-1717308887430.png

 

 

thanks,

if it resolved your query, kindly mark it as solution and give thumps Up!

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