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Date one year from date

Is there a way to add 1 year to a date? Not 365 days, because that will break every leap year. I understand addDays is the expression I would use.

 

Thanks,

Anne

5 ACCEPTED SOLUTIONS

Accepted Solutions
Pstork1
Most Valuable Professional
Most Valuable Professional

Use the AddToTime() function and use "Year" as the interval.  Its the generic version of AddDays().



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I think addDays would be more reliable than simply replacing the year, because if you just change the year, that day might not exist a year into the future. But anyway, you can just replace the year part of the date with the current year plus one, you could do it like this:

 

replace
(
    outputs('date'), 
    formatDateTime(utcNow(), 'yyyy'),
    string(add(int(formatDateTime(utcNow(), 'yyyy')),1))	
)

 

It just replaces the current year, with next year. I think I would still use addDays though.

 

Replied at the same time as @Pstork1 - his response is much better! 😂

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Pstork1
Most Valuable Professional
Most Valuable Professional

Calculate the date for a year in advance and then test it to find what day it is.  If its weekend add or subtract a day to get to Friday or Monday.



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Pstork1
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Most Valuable Professional

I did some testing and it will work even if the input date is 2/29 in Leap year.  But it doesn't seem very sophisticated.  If I input 2/29/2024 and add a year I get 2/28/2025.  If I add 4 years I get 2/29/2028.  So it only deals with Leap year when processing Leap Day.  Otherwise it basically just changes the year.



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View solution in original post

Use Add to Datetime activity and add 1 year in the options !!

View solution in original post

14 REPLIES 14
Pstork1
Most Valuable Professional
Most Valuable Professional

Use the AddToTime() function and use "Year" as the interval.  Its the generic version of AddDays().



-------------------------------------------------------------------------
If I have answered your question, please mark your post as Solved.
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I think addDays would be more reliable than simply replacing the year, because if you just change the year, that day might not exist a year into the future. But anyway, you can just replace the year part of the date with the current year plus one, you could do it like this:

 

replace
(
    outputs('date'), 
    formatDateTime(utcNow(), 'yyyy'),
    string(add(int(formatDateTime(utcNow(), 'yyyy')),1))	
)

 

It just replaces the current year, with next year. I think I would still use addDays though.

 

Replied at the same time as @Pstork1 - his response is much better! 😂

Thanks! Now a follow-up question: is there a way to force the date 1 year in the future to be the nearest weekday? In other words, if the date 1 year in the future falls on a weekend, it would show the Friday or Monday closest to that day. Any help greatly appreciated.

 

Anne

Would that break if the date was calculated one year from Leap Day?

 

Anne

Pstork1
Most Valuable Professional
Most Valuable Professional

Calculate the date for a year in advance and then test it to find what day it is.  If its weekend add or subtract a day to get to Friday or Monday.



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Pstork1
Most Valuable Professional
Most Valuable Professional

I did some testing and it will work even if the input date is 2/29 in Leap year.  But it doesn't seem very sophisticated.  If I input 2/29/2024 and add a year I get 2/28/2025.  If I add 4 years I get 2/29/2028.  So it only deals with Leap year when processing Leap Day.  Otherwise it basically just changes the year.



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ChadVKealey
Memorable Member
Memorable Member

@Pstork1 , I'm working on a "task schedule" for our university's registrar. They have events/tasks that need to recur every year on the same day of week. For example, "Verify faculty enrollments" needs to happen on the Monday of week 1 in our fall quarter. In 2020, that was 9/21/2020. This year, it was 9/20/2020. Using "addToTime(<start-time>,1, 'Year')" would (as noted above) simply replace the year, resulting in this year's iteration landing on Tuesday, 9/21/2021. I suspect that simply subtracting one day will do the trick (with the caveat that some manual oversight will be needed), but not sure if I should subtract it before or after adding the year, or if it even matters. So, use:

 

addToTime(subtractFromTime(<start-date>,1,'Day'),1,'Year')

OR

subtractFromTime(addToTime(<start-time>,1,'Year'),1,'Day')

 

EDIT: When it comes to dealing with leap year, the order matters. You need to add a year, then subtract a day (the second formula) to keep it on the same day of the week.

 

  • Start date: 2020-02-29 = Saturday 02-29-2020
  • addToTime(date,1,'Year'): 2021-02-28T00:00:00.0000000 = Sunday 02-28-2021
  • addToTime(subtractFromTime(date,1,'Day'),1,'Year'): 2021-02-28T00:00:00.0000000 = Sunday 02-28-2021
  • subtractFromTime(addToTime(date,1,'Year'),1,'Day'): 2021-02-27T00:00:00.0000000 = Saturday 02-27-2021

Rather than adding a day and subtracting a year why not just add 364 days?  That will give the same result.

addDays(<start time>,364)


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True...that is simpler. I was kind of stuck on using "addToTime" to keep things "leap year aware". Actually, testing with dates just before/after leap day shows that just adding 364 days works, while neither other method proves to be reliable. Thanks!

if i use this in Power automate desktop , it giving as text vaule , but not date output

MitheshRpa_0-1679557599793.png

 

Use Add to Datetime activity and add 1 year in the options !!

Pstork1
Most Valuable Professional
Most Valuable Professional

Power Automate Desktop has no support for functions.  As @MitheshRpa mentions you have to use an action instead of a function.



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Thanks very kindly.

 

A

This explanation is terrible, and does not work!

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