cancel
Showing results for 
Search instead for 
Did you mean: 
Reply
Hamillkw
Frequent Visitor

Get an Array of random results from a SharePoint List.

I have a SharePoint List where I need to get a number of items and then mark them as selected.  After reading a couple of articles on how to do this I settled on a method that seems to reliably produce a random item just not a different item each time. the problem seems to be that the filter array is not doing its job. From a very small pool of 4 items, I'm asking for 3. About half the time I get two of one or all three of them the same.  when I look at the output the Filter Array isn't taking out the selected item (the Get Item Output) in the Do until loop. I am using the ID field as the identifier for the item.  Is it possible that the SharePoint list ID field is just the wrong field?

Thank you in advance for your assistance

 

Do Until LoopDo Until Loop

 

1 ACCEPTED SOLUTION

Accepted Solutions

If I'm understanding what you're after, this is how I would build the flow.

 

For this example, I'm using the following SharePoint List where I want to get a certain number of random items.

grantjenkins_0-1674560270577.png

 

See full flow below. I'll go into each of the actions.

grantjenkins_1-1674560311442.png

 

Manually trigger a flow has a single Number input. This is the number of random items I want to return. If the number of items you wanted was always the same, then you could skip having an input here.

grantjenkins_2-1674560397622.png

 

Get items returns all the items from the SharePoint list.

grantjenkins_3-1674560437197.png

 

Select uses the output from Get items and Maps the ID field and another custom field called Order that uses the rand function to generate a random number for each item. The expression used is below.

rand(1, 1000)

grantjenkins_4-1674560566260.png

 

This would output something like that below which includes the ID for each item, and a random number between 1 and 1000.

grantjenkins_5-1674560684069.png

 

Select IDs uses the output from Select, but firstly, sorts it by the Order property (our random number), then takes N number of items. In this example, N is the number we entered in our trigger. The expressions used here are:

//From
take(sort(body('Select'), 'Order'), triggerBody()['number'])

//Map
item()?['ID']


//Note that if it was always the same number of random items you wanted, then you could hardcode it as so, where it takes the first 3 items.
take(sort(body('Select'), 'Order'), 3)

grantjenkins_6-1674560913413.png

 

If we had entered 3 as our trigger input, then we would end up with a simple array of 3 random IDs.

grantjenkins_7-1674561006911.png

 

Lastly, our Filter array will use the output from our Get items and use the output from Select IDs in the filter. Effectively, the filter will be where the array of IDs contains the ID of the list item.

grantjenkins_9-1674561136620.png

 

Our Filter array would now contain N number of random items from our SharePoint List. You could then use an Apply to each to iterate over the Filter array and do whatever you need to.


----------------------------------------------------------------------
If I've answered your question, please mark the post as Solved.
If you like my response, please consider giving it a Thumbs Up.


----------------------------------------------------------------------
If I've answered your question, please mark the post as Solved.
If you like my response, please consider giving it a Thumbs Up.

View solution in original post

8 REPLIES 8
Expiscornovus
Most Valuable Professional
Most Valuable Professional

Hi @Hamillkw,

 

Out of interest, do you always want to use 3 of the 4 items?

 

If that is the case can't you exclude one random item instead? Safes you the trouble of keeping track which items already have been picked 😁



Happy to help out! 🙂

Interested in more #PowerAutomate #SharePointOnline or #MicrosoftCopilotStudio content?
Visit my blog, Subscribe to my YouTube channel or Follow me on Twitter


If I'm understanding what you're after, this is how I would build the flow.

 

For this example, I'm using the following SharePoint List where I want to get a certain number of random items.

grantjenkins_0-1674560270577.png

 

See full flow below. I'll go into each of the actions.

grantjenkins_1-1674560311442.png

 

Manually trigger a flow has a single Number input. This is the number of random items I want to return. If the number of items you wanted was always the same, then you could skip having an input here.

grantjenkins_2-1674560397622.png

 

Get items returns all the items from the SharePoint list.

grantjenkins_3-1674560437197.png

 

Select uses the output from Get items and Maps the ID field and another custom field called Order that uses the rand function to generate a random number for each item. The expression used is below.

rand(1, 1000)

grantjenkins_4-1674560566260.png

 

This would output something like that below which includes the ID for each item, and a random number between 1 and 1000.

grantjenkins_5-1674560684069.png

 

Select IDs uses the output from Select, but firstly, sorts it by the Order property (our random number), then takes N number of items. In this example, N is the number we entered in our trigger. The expressions used here are:

//From
take(sort(body('Select'), 'Order'), triggerBody()['number'])

//Map
item()?['ID']


//Note that if it was always the same number of random items you wanted, then you could hardcode it as so, where it takes the first 3 items.
take(sort(body('Select'), 'Order'), 3)

grantjenkins_6-1674560913413.png

 

If we had entered 3 as our trigger input, then we would end up with a simple array of 3 random IDs.

grantjenkins_7-1674561006911.png

 

Lastly, our Filter array will use the output from our Get items and use the output from Select IDs in the filter. Effectively, the filter will be where the array of IDs contains the ID of the list item.

grantjenkins_9-1674561136620.png

 

Our Filter array would now contain N number of random items from our SharePoint List. You could then use an Apply to each to iterate over the Filter array and do whatever you need to.


----------------------------------------------------------------------
If I've answered your question, please mark the post as Solved.
If you like my response, please consider giving it a Thumbs Up.


----------------------------------------------------------------------
If I've answered your question, please mark the post as Solved.
If you like my response, please consider giving it a Thumbs Up.

That's an Interesting idea but sadly no. I expect to in the end to get 3-9 selections from pools of approximately 100. 

Thanks for your idea,

 

This Solution is certainly interesting, however, Power Automate insists on wrapping Select ID in an Apply to Each. It gives the following error if I don't: 

 

 'InvalidTemplate' and message 'The template validation failed: 'The repetition action(s) 'Apply_to_each' referenced by 'inputs' in action 'Select_ID' are not defined in the template.'.'.

 

If I do this though, the Filter Array contains no output. 

Perhaps I'm not applying the solution correctly?

Hamillkw_0-1674679729352.png

 

 

 




@Hamillkw Are you able to show the design of your flow including what you've put as inputs, etc?


----------------------------------------------------------------------
If I've answered your question, please mark the post as Solved.
If you like my response, please consider giving it a Thumbs Up.

Thank you Grant,

 

I copied your solution and attached the SharePoint List I'm using and applied an update item at the end. as you can see Power Automate wants to wrap the Select ID  in an Apply to Each. 
 Am I misunderstanding something? is the Select ID not a Select Data Operation? 

Hamillkw_1-1674743867719.png

 

 

 

Can you show what your inputs are for your Select ID? That's where the issue is as it looks like you're trying to use something in there from Get items but shouldn't be.

 

The input would be as follows:

 

//From
take(sort(body('Select'), 'Order'), triggerBody()['number'])

//Map
item()?['ID']


//Note that if it was always the same number of random items you wanted, then you could hardcode it as so, where it takes the first 3 items.
take(sort(body('Select'), 'Order'), 3)

 


----------------------------------------------------------------------
If I've answered your question, please mark the post as Solved.
If you like my response, please consider giving it a Thumbs Up.

thank you Grant,

you are correct I applied the solution incorrectly, I have tested it several times and not gotten the same ID twice in one selection. I will test it on a larger pool and let you know. 

Helpful resources

Announcements

Community will be READ ONLY July 16th, 5p PDT -July 22nd

Dear Community Members,   We'd like to let you know of an upcoming change to the community platform: starting July 16th, the platform will transition to a READ ONLY mode until July 22nd.   During this period, members will not be able to Kudo, Comment, or Reply to any posts.   On July 22nd, please be on the lookout for a message sent to the email address registered on your community profile. This email is crucial as it will contain your unique code and link to register for the new platform encompassing all of the communities.   What to Expect in the New Community: A more unified experience where all products, including Power Apps, Power Automate, Copilot Studio, and Power Pages, will be accessible from one community.Community Blogs that you can syndicate and link to for automatic updates. We appreciate your understanding and cooperation during this transition. Stay tuned for the exciting new features and a seamless community experience ahead!

Summer of Solutions | Week 4 Results | Winners will be posted on July 24th

We are excited to announce the Summer of Solutions Challenge!    This challenge is kicking off on Monday, June 17th and will run for (4) weeks.  The challenge is open to all Power Platform (Power Apps, Power Automate, Copilot Studio & Power Pages) community members. We invite you to participate in a quest to provide solutions to as many questions as you can. Answers can be provided in all the communities.    Entry Period: This Challenge will consist of four weekly Entry Periods as follows (each an “Entry Period”)   - 12:00 a.m. PT on June 17, 2024 – 11:59 p.m. PT on June 23, 2024 - 12:00 a.m. PT on June 24, 2024 – 11:59 p.m. PT on June 30, 2024 - 12:00 a.m. PT on July 1, 2024 – 11:59 p.m. PT on July 7, 2024 - 12:00 a.m. PT on July 8, 2024 – 11:59 p.m. PT on July 14, 2024   Entries will be eligible for the Entry Period in which they are received and will not carryover to subsequent weekly entry periods.  You must enter into each weekly Entry Period separately.   How to Enter: We invite you to participate in a quest to provide "Accepted Solutions" to as many questions as you can. Answers can be provided in all the communities. Users must provide a solution which can be an “Accepted Solution” in the Forums in all of the communities and there are no limits to the number of “Accepted Solutions” that a member can provide for entries in this challenge, but each entry must be substantially unique and different.    Winner Selection and Prizes: At the end of each week, we will list the top ten (10) Community users which will consist of: 5 Community Members & 5 Super Users and they will advance to the final drawing. We will post each week in the News & Announcements the top 10 Solution providers.  At the end of the challenge, we will add all of the top 10 weekly names and enter them into a random drawing.  Then we will randomly select ten (10) winners (5 Community Members & 5 Super Users) from among all eligible entrants received across all weekly Entry Periods to receive the prize listed below. If a winner declines, we will draw again at random for the next winner.  A user will only be able to win once overall. If they are drawn multiple times, another user will be drawn at random.  Individuals will be contacted before the announcement with the opportunity to claim or deny the prize.  Once all of the winners have been notified, we will post in the News & Announcements of each community with the list of winners.   Each winner will receive one (1) Pass to the Power Platform Conference in Las Vegas, Sep. 18-20, 2024 ($1800 value). NOTE: Prize is for conference attendance only and any other costs such as airfare, lodging, transportation, and food are the sole responsibility of the winner. Tickets are not transferable to any other party or to next year’s event.   ** PLEASE SEE THE ATTACHED RULES for this CHALLENGE**   Week 1 Results: Congratulations to the Week 1 qualifiers, you are being entered in the random drawing that will take place at the end of the challenge.   Community MembersNumber SolutionsSuper UsersNumber Solutions Deenuji 9 @NathanAlvares24  17 @Anil_g  7 @ManishSolanki  13 @eetuRobo  5 @David_MA  10 @VishnuReddy1997  5 @SpongYe  9JhonatanOB19932 (tie) @Nived_Nambiar  8 @maltie  2 (tie)   @PA-Noob  2 (tie)   @LukeMcG  2 (tie)   @tgut03  2 (tie)       Week 2 Results: Congratulations to the Week 2 qualifiers, you are being entered in the random drawing that will take place at the end of the challenge. Week 2: Community MembersSolutionsSuper UsersSolutionsPower Automate  @Deenuji  12@ManishSolanki 19 @Anil_g  10 @NathanAlvares24  17 @VishnuReddy1997  6 @Expiscornovus  10 @Tjan  5 @Nived_Nambiar  10 @eetuRobo  3 @SudeepGhatakNZ 8     Week 3 Results: Congratulations to the Week 3 qualifiers, you are being entered in the random drawing that will take place at the end of the challenge. Week 3:Community MembersSolutionsSuper UsersSolutionsPower Automate Deenuji32ManishSolanki55VishnuReddy199724NathanAlvares2444Anil_g22SudeepGhatakNZ40eetuRobo18Nived_Nambiar28Tjan8David_MA22   Week 4 Results: Congratulations to the Week 4 qualifiers, you are being entered in the random drawing that will take place at the end of the challenge. Week 4:Community MembersSolutionsSuper UsersSolutionsPower Automate Deenuji11FLMike31Sayan11ManishSolanki16VishnuReddy199710creativeopinion14Akshansh-Sharma3SudeepGhatakNZ7claudiovc2CFernandes5 misc2Nived_Nambiar5 Usernametwice232rzaneti5 eetuRobo2   Anil_g2   SharonS2  

Check Out | 2024 Release Wave 2 Plans for Microsoft Dynamics 365 and Microsoft Power Platform

On July 16, 2024, we published the 2024 release wave 2 plans for Microsoft Dynamics 365 and Microsoft Power Platform. These plans are a compilation of the new capabilities planned to be released between October 2024 to March 2025. This release introduces a wealth of new features designed to enhance customer understanding and improve overall user experience, showcasing our dedication to driving digital transformation for our customers and partners.    The upcoming wave is centered around utilizing advanced AI and Microsoft Copilot technologies to enhance user productivity and streamline operations across diverse business applications. These enhancements include intelligent automation, AI-powered insights, and immersive user experiences that are designed to break down barriers between data, insights, and individuals. Watch a summary of the release highlights.    Discover the latest features that empower organizations to operate more efficiently and adaptively. From AI-driven sales insights and customer service enhancements to predictive analytics in supply chain management and autonomous financial processes, the new capabilities enable businesses to proactively address challenges and capitalize on opportunities.    

Updates to Transitions in the Power Platform Communities

We're embarking on a journey to enhance your experience by transitioning to a new community platform. Our team has been diligently working to create a fresh community site, leveraging the very Dynamics 365 and Power Platform tools our community advocates for.  We started this journey with transitioning Copilot Studio forums and blogs in June. The move marks the beginning of a new chapter, and we're eager for you to be a part of it. The rest of the Power Platform product sites will be moving over this summer.   Stay tuned for more updates as we get closer to the launch. We can't wait to welcome you to our new community space, designed with you in mind. Let's connect, learn, and grow together.   Here's to new beginnings and endless possibilities!   If you have any questions, observations or concerns throughout this process please go to https://aka.ms/PPCommSupport.   To stay up to date on the latest details of this migration and other important Community updates subscribe to our News and Announcements forums: Copilot Studio, Power Apps, Power Automate, Power Pages

Users online (1,186)