How can I trigger a button on another page?

[xxtheextraxx]

Hello ,

I watched Reza's video and copied the menubar. Unfortunately, the navigation bar must first be triggered by a button in order to display the content. I thought that when the user logs in on another screen, the Login button on the other screen triggers the button for the menubar and is then no longer visible. I couldn't get it to work, I thought I could do it with a global variable or with a flow but I can't manage it. Do you have any ideas?

Thanks for your answers 🙂

[BCBuizer]

Hi @xxtheextraxx ,

You can use the Select function for that:

Select(ButtonName)

[xxtheextraxx]

Powerapps says that the button is not displayed on the screen. What am I doing wrong?

[BCBuizer · Accepted solution]

Hi @xxtheextraxx ,

I spoke too soon: Indeed Select can't be used for a control off screen: https://powerusers.microsoft.com/t5/Building-Power-Apps/DisplayMode-View-removes-border/td-p/66973

A workaround may be to use a global variable and set that with a random value:

Set(varTrigger,Rand())

On the screen that has the control you want to trigger, insert a slider with the following properties:

Default = varTrigger
Visible = false
OnChange = Select(ButtonName)

The Slider.Onchange property will be triggered every time varTrigger is changed and because it is on the same screen as the button you want to select, there's no issue.

[xxtheextraxx]

Thank you so much

[xxtheextraxx]

It now jumps all the time to the structure view with the data my button saves and blocks all the time. Have I done something wrong or does it stay like this?

[BCBuizer]

Hi @xxtheextraxx ,

Without knowing how you implemented this, it's really hard to say anything useful. All I can say is to beware of creating loops.

For further support, please explain step-by-step how this is supposed to work, including the code, so I can check it.

[hguenther]

Hey @BCBuizer ,

I tried to implement it in the way you suggested. On the "OnSucess"-Property of a form I want to select a button which is on another screen. When successfully submitting the form, varTrigger is changed, but I fear that the button will not be selected, beacuse the desired action is not executed. Do you have any suggestions? Thanks in advance!

[BCBuizer]

Hi @hguenther ,

In cases where this didn't work I used canvas components to build a button which you can then add to multiple screens but you don't have to worry about synchronising any changes across multiple instances of the component, something that would happen if you were to simply copy the button: https://learn.microsoft.com/en-us/power-apps/maker/canvas-apps/create-component

Once created, you can simply add a button to any screen where you need it and then select it using the Select function.