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MichaelVaughan
Frequent Visitor

Ready for Foster

Hi all,

 

I am struggling again, I am trying to filter the Gallary in the 'Items' field. based on the selected shelter in the dropdown list and animals that are ready for fostering. I have made the first part of this work, it filters by shelter name, but I can not get it to show only animals marked as 'Ready for Adoption', no matter what I have tried.

 

Filter(
Search(
'Adoption Animals',
ddlShelter.Selected.'Shelter Name',
'Shelter Name'
),
'Shelter Status (Adoption Animals)'.Value = "188,880,001"

 

 

This is what the choices look like in my Shelter Status Column: 

MichaelVaughan_0-1720956021263.png

 

 

Any help would be hugely appreciated.

 

Many thanks,

Michael

1 ACCEPTED SOLUTION

Accepted Solutions
BCBuizer
Multi Super User
Multi Super User

Hi @MichaelVaughan 

 

My two cents:

1. Instead of using Search to filter the entries per shelter name, you can simply add a condition to the filter.

2. If you want to filter by a choice option, you don't need to select .Value when using Dataverse.

 

This will make your formula look something like this: 

Filter(
	'Adoption Animals',
	'Shelter Name' = ddlShelter.Selected.'Shelter Name',
	'Shelter Status (Adoption Animals)' = 'Shelter Status'.'Ready for Adoption'
)

 



Did you like my post? Please give it a thumbs up! Did I resolve your issue? Please click Accept as Solution to close the topic and so other members of the community can find solutions more easily.

View solution in original post

2 REPLIES 2
BCBuizer
Multi Super User
Multi Super User

Hi @MichaelVaughan 

 

My two cents:

1. Instead of using Search to filter the entries per shelter name, you can simply add a condition to the filter.

2. If you want to filter by a choice option, you don't need to select .Value when using Dataverse.

 

This will make your formula look something like this: 

Filter(
	'Adoption Animals',
	'Shelter Name' = ddlShelter.Selected.'Shelter Name',
	'Shelter Status (Adoption Animals)' = 'Shelter Status'.'Ready for Adoption'
)

 



Did you like my post? Please give it a thumbs up! Did I resolve your issue? Please click Accept as Solution to close the topic and so other members of the community can find solutions more easily.

Hi!  I was working on the gallery to show animals ready for foster: I used this formula in item:

 

Filter(
    'Animal informations',
    'Shelter Name (Shelter informations)'= DDMenu.Selected.'Shelter Name',
    'Shelter Status (Animal informations)' = 'Shelter Status (Animal informations)'.'Ready for Foster')

 

IgnacioG_0-1721501452026.png

 

However it's not working... anyone knows why? Thanks in advance!. 

 

Ignacio

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